#### Question

Price P for demand D is given as P = 183 +120D - 3D^{2} Find D for which the price is increasing

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#### Solution

Price function P is given by

`P=183+120D-3D^2`

Differentiating w.r.t. D

`"dP"/"dD"=120-6D`

If price is increasing then we have

`"dP"/"dD">0`

120-6D >0

6D <120

D<20

if the demand is less than units then Price increases

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Solution for question: price P for demand D is given as P = 183 +120D - 3D2 Find D for which the price is increasing concept: null - Increasing and Decreasing Functions. For the courses HSC Science (Computer Science), HSC Science (General) , HSC Arts, HSC Science (Electronics), HSC Commerce, HSC Commerce (Marketing and Salesmanship)