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Solution for Find the Intervals in Which F(X) is Increasing Or Decreasing F(X) = Sinx + |Sinx|, 0 < X ≤ 2 π ? - CBSE (Commerce) Class 12 - Mathematics

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Question

Find the interval in which f(x) is increasing or decreasing f(x) = sinx + |sin x|, 0 < x \[\leq 2\pi\] ?

Solution

\[ f\left( x \right) = \sin x + \left| \sin x \right|, 0 < x \leq 2\pi\]

\[\text { Case I: When x }\in \left( 0, \pi \right)\]

\[f\left( x \right) = \sin x + \sin x = 2\sin x\]

\[ \Rightarrow f'\left( x \right) = 2\cos x\]

\[\text { As,} \cos x > 0 \text { for } x \in \left( 0, \frac{\pi}{2} \right) \text { and }\cos x < 0 \text { for } x \in \left( \frac{\pi}{2}, \pi \right)\]

\[\text { So,} f'\left( x \right) > 0\text { for} x \in \left( 0, \frac{\pi}{2} \right)\text{  and } f'\left( x \right) < 0 \text { for }x \in \left( \frac{\pi}{2}, \pi \right)\]

\[ \therefore f\left( x \right)\text {  is increaing on} \left( 0, \frac{\pi}{2} \right) \text { and } f\left( x \right) \text { is decreasing on } \left( \frac{\pi}{2}, \pi \right) . \]

\[\text { Case II: When x } \in \left( \pi, 2\pi \right)\]

\[f\left( x \right) = \sin x - \sin x = 0\]

\[ \Rightarrow f'\left( x \right) = 0\]

\[\text { So,} f\left( x \right) \text { is neither increaing nor decreasing on } \left( \pi, 2\pi \right) . \]

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Solution for question: Find the Intervals in Which F(X) is Increasing Or Decreasing F(X) = Sinx + |Sinx|, 0 < X ≤ 2 π ? concept: Increasing and Decreasing Functions. For the courses CBSE (Commerce), CBSE (Arts), PUC Karnataka Science, CBSE (Science)
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