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In Young' S Experiment the Ratio of Intensity at the Maxima and Minima . in the Interference Pattern is 36 : 16. What is the Ratio of the Widths of the Two Slits? - Physics

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In Young' s experiment the ratio of intensity at the maxima and minima . in the interference pattern is 36 : 16. What is the ratio of the widths of the two slits?

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Solution

`I_(max)/I_(min)=((A_1/A_2+1)/(A_1/A_2-1))^2`

`Let A_1/A_2=r`

`therefore I_(max)/I_(min)=((r+1)/(r-1))^2`

`therefore 36/16=((r+1)/(r-1))^2`

`therefore 6/4=((r+1)/(r-1))`

`therefore r=5/1`

`A_1/A_2=5/1`

Ratio of width `=(A_1/A_2)^2=25/1`

Concept: Interference of Light Waves and Young’S Experiment
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