MCQ

In which of the following systems will the wavelength corresponding to *n* = 2 to *n* = 1 be minimum?

#### Options

Hydrogen atom

Deuterium atom

Singly ionized helium

Doubly ionized lithium

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#### Solution

Doubly ionized lithium

The wavelength corresponding the transition from* **n*_{2} to *n*_{1} is given by

`1/lamda =RZ^2 (1/n_1^2 - 1/n_2^2)`]

Here,*R* = Rydberg constant*Z* = Atomic number of the ion

From the given formula, it can be observed that the wavelength is inversely proportional to the square of the atomic number.

Therefore, the wavelength corresponding to *n* = 2 to *n* = 1 will be minimum in doubly ionized lithium ion because for lithium, *Z* = 3.

Concept: Bohr'S Model for Hydrogen Atom

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