Advertisement Remove all ads

In the Truss Shown in Figure,Compute the Forces in Each Member. - Engineering Mechanics

Advertisement Remove all ads
Advertisement Remove all ads
Answer in Brief

In the truss shown in figure,compute the forces in each member.

Advertisement Remove all ads

Solution

Solution :
We can say that FD,GH and CB are zero force members in the given truss
Joint A :

Applying the conditions of equilibrium
ΣFy=0
-1 – FAC sin30 = 0
FAC = -2kN
Applying the conditions of equilibrium
ΣFx = 0
FAB + FAC cos30 = 0
FAB = 1.7321 Kn
JOINT C :

Applying the conditions of equilibrium
ΣFx = 0
FCE = FCA = -2kN
JOINT B :

Applying the conditions of equilibrium
ΣFy = 0
-1 - FBE sin60 = 0
FBE = -1.1547 kN
Applying the conditions of equilibrium
ΣFx = 0
-FBA + FBEcos60 + FBD = 0
FBD = 2.3094 kN
JOINT D :

Applying the conditions of equilibrium
ΣFy = 0
-1 - FDEsin60 = 0
FDE = -1.1547 kN
Applying the conditions of equilibrium
ΣFx = 0
-FDB - FDEcos60 + FDG = 0
FDG = 1.7321 kN
JOINT E :

Applying the conditions of equilibrium
ΣFy = 0
FED + FEFcos30 + FEBsin30 = 0
FEFcos30 = -(-1.1547)-(-1.1547) x`1/2`
FEF = 2kN
Joint F :

Applying the conditions of equilibrium
ΣFx = 0
FFG = FFE = -2kN
Final answer :

Sr.no. MEMBER MAGNITUDE OF FORCE (in kN) NATURE OF FORCE
1. AC 2 COMPRESSION
2. AB 1.7321 TENSION
3. CB 0 -
4. CE 2 COMPRESSION
5. BE 1.1547 COMPRESSION
6. BD 2.3094 TENSION
7. DE 1.1547 COMPRESSION
8.. DG 1.7321 TENSION
9. EF 2 TENSION
10. EH 4 COMPRESSION
11. FD 0 -
12. FG 2 COMPRESSION
13. GH 0 -
Concept: Analysis of Plane Trusses by Using Method of Joints
  Is there an error in this question or solution?
Advertisement Remove all ads
Advertisement Remove all ads
Share
Notifications

View all notifications


      Forgot password?
View in app×