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In Triangle Abc , If ∠1 = ∠2, Prove that `"Ab"/"Ac"="Bd"/"Dc"` - Mathematics

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Question

In ΔABC , if ∠1 = ∠2, prove that `"AB"/"AC"="BD"/"DC"`

Solution

Given: A ΔABC in which ∠1 = ∠2

To prove: `"AB"/"AC"="BD"/"DC"`

Construction: Draw CE || DA to meet BA produced in E.

Proof: since, CE || DA and AC cuts them.

∴ ∠2 − ∠3 …. (i) [Alternate angles]

And, ∠1 − ∠4 ….(ii) [Corresponding angles]

But, ∠1 − ∠2 [Given]

From (i) and (ii), we get

∠3 − ∠4

Thus, in ΔACE, we have

∠3 = ∠4

⇒ AE = AC … (iii) [Sides opposite to equal angles are equal]

Now, In ΔBCE, we have

DA || CE

`rArr"BD"/"DC"="BA"/"AE"`    [Using basic proportionality theorem]

`rArr"BD"/"DC"="AB"/"AC"`     [∵ BA – AB and AE – AC from (iii)]

Hence, `"AB"/"AC"="BD"/"DC"`

  Is there an error in this question or solution?

APPEARS IN

 RD Sharma Solution for Class 10 Maths (2018 (Latest))
Chapter 7: Triangles
Ex. 7.3 | Q: 6 | Page no. 32
 RD Sharma Solution for Class 10 Maths (2018 (Latest))
Chapter 7: Triangles
Ex. 7.3 | Q: 6 | Page no. 32

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Solution In Triangle Abc , If ∠1 = ∠2, Prove that `"Ab"/"Ac"="Bd"/"Dc"` Concept: Angle Bisector.
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