#### Question

In the given figure, radius of the circle is 7 cm and m ( arc MBN) = 60

^{°},find A(O - MBN) .

#### Solution

Radius of the circle, r = 7 cm

m(arc MBN) = ∠MON = θ = 60º

Area of the sector =` theta/360 xx pir^2`

⇒ Area ( O - MBN ) =`60/360 `× Area of circle

Area of the sector = \[\frac{\theta}{360º} \times \pi r^2 = \frac{60º}{360º } \times \frac{22}{7} \times \left( 7 \right)^2\] = 25.7 cm^{2}

⇒ A(O- MBN) = 25.7 sq. cm

Is there an error in this question or solution?

Solution In the Given Figure, Radius of the Circle is 7 Cm and M ( Arc Mbn) = 60°,Find A(O - Mbn) . Concept: Perimeter and Area of a Circle.