Sum

In the given figure, ∠CAB = 25°, find ∠BDC, ∠DBA and ∠COB

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#### Solution

In ΔACP,

∠ACP = 180° – (25° + 90°)

= 180° – 115°

= 65°

∠CBA = ∠CAB = 25° ...[Both the angles are standing in the same base]

∠DBA = 65° ...[∠DBA and ∠BCA standing in the same base]

∠COB = 50°

Concept: Theorem: Angles in the Same Segment of a Circle Are Equal.

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