Sum
In the given figure, AC is the diameter of the circle with centre O. If ∠ADE = 30°, ∠DAC = 35° and ∠CAB = 40°. Find ∠ACD
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Solution
∠ADC = 90° ...(Angle in a semi-circle)
∠ADC + ∠ACD + ∠DAC = 180° ...(Sum of the angles of a triangle is 180°)
90° + ∠ACD + 35° = 180°
∠ACD = 180° – 125°
∠ACD = 55°
Concept: Exterior Angle of a Cyclic Quadrilateral
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