Share

# In a Single Throw of Two Dice, Find the Probability Of: a Doublet - Mathematics

Course

#### Question

In a single throw of two dice, find the probability of:

a doublet

#### Solution

The  number of possible outcomes is 6xx6=36,  We write them as given below:

1,11,21,,31,41,51,6

2,12,22,32,42,52,6

3,13,23,33,43,53,6

4,14,24,34,44,54,6

5,15,25,35,45,55,6

6,16,26,36,46,56,6

n(s)=36

E= Event of getting a doublet={(1,1)(2,2)(3,3)(4,4)(5,5)(6,6)}

n(E)=6

Probability of getting a doublet = (n(E))/(n(S))=6/36=1/6

Is there an error in this question or solution?