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In a Simultaneous Throw of a Pair of Dice, Find the Probability of Getting:(Xiii) Odd Number on the First and 6 on the Second - Mathematics

In a simultaneous throw of a pair of dice, find the probability of getting odd number on the first and 6 on the second

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Solution

We know that in a single throw of two dices, the total number of possible outcomes is (6 × 6) = 36.
Let S be the sample space.
Then n(S) = 36

 Let E13 = event of getting an odd number on the first throw and 6 on the second
 Then E13 = {(1,6), (3, 6), (5, 6)}
         i.e. n (E13) = 3

\[\therefore P\left( E_{13} \right) = \frac{n\left( E_{13} \right)}{n\left( S \right)} = \frac{3}{36} = \frac{1}{12}\]

Concept: Probability - Probability of 'Not', 'And' and 'Or' Events
  Is there an error in this question or solution?
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APPEARS IN

RD Sharma Class 11 Mathematics Textbook
Chapter 33 Probability
Exercise 33.3 | Q 2.13 | Page 45
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