# In a Simultaneou Throw of a Pair of Dice, Find the Probability of Getting: a Doublet of Odd Numbers - Mathematics

In a simultaneou throw of a  pair of dice, find the probability of getting:

a doublet of odd numbers

#### Solution

$\text{ When a pair of dice is thrown simultaneously, the sample space will be as follow }:$
$S = \left\{ \left( 1, 1 \right), \left( 1, 2 \right), \left( 1, 3 \right), \left( 1, 4 \right), \cdots\left( 6, 5 \right), \left( 6, 6 \right) \right\}$
$\text{ Hence, the total number of outcomes is 36 }.$

$\text{ Let A be the event of getting doublets of odd numbers in the sample space } .$
$\text{ The doublets of odd numbers in the sample space are } \left( 1, 1 \right), \left( 3, 3 \right) \text{ and } \left( 5, 5 \right) .$
$\text{ Hence, the number of favourable outcomes is 3 } .$
$\therefore P\left( A \right) = \frac{\text{ Number of favourable outcomes }}{\text{ Total number of outcomes }} = \frac{3}{36} = \frac{1}{12}$

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#### APPEARS IN

RD Sharma Class 8 Maths
Chapter 26 Data Handling-IV (Probability)
Exercise 26.1 | Q 3.04 | Page 15