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In Shuffling a Pack of 52 Playing Cards, Four Are Accidently Dropped; Find the Chance that the Missing Cards Should Be One from Each Suit. - Mathematics

In shuffling a pack of 52 playing cards, four are accidently dropped; find the chance that the missing cards should be one from each suit.

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Solution

It is given that from a well-shuffled pack of cards, four cards are missing out.
∴ Total number of elementary events, n(S) = 52C4
Let E be the event where four cards are missing from each suit.
i.e. n(E)= 13C1 × 13C1 × 13C1 × 13C1
Hence, required probability = \[\frac{n\left( E \right)}{n\left( S \right)} = \frac{^{13}{}{C}_1 \times ^{13}{}{C}_1 \times ^{13}{}{C}_1 \times ^{13}{}{C}_1}{^{52}{}{C}_4}\]

\[= \frac{13 \times 13 \times 13 \times 13}{\frac{52 \times 51 \times 50 \times 49}{4 \times 3 \times 2 \times 1}}\]
\[ = \frac{13 \times 13 \times 13 \times 13}{13 \times 17 \times 25 \times 49}\]
\[ = \frac{2197}{20825}\]

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APPEARS IN

RD Sharma Class 11 Mathematics Textbook
Chapter 33 Probability
Exercise 33.3 | Q 11 | Page 46
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