# In a Right Angled Triangle Abc, Write the Value of Sin2 a + Sin2 B + Sin2 C. - Mathematics

Short Note

In a right angled triangle ABC, write the value of sin2 A + Sin2 B + Sin2 C.

#### Solution

$Let, \angle B = 90°$
$\therefore A + C = 90°= \frac{\pi}{2}$
$\Rightarrow C = \frac{\pi}{2} - A$
$\Rightarrow \sin C = \sin \left( \frac{\pi}{2} - A \right)$
$\Rightarrow \sin C = \cos A . . . \left( i \right)$
$\text{ Now,}$
$\sin^2 A + \sin^2 B + \sin^2 C = \sin^2 A + 1 + \sin^2 C \left( \because \sin B = \sin 90°= 1 \right)$
$= \sin^2 A + \cos^2 A + 1 \left[ \text{ Using } \left( i \right) \right]$
$= 1 + 1$
$= 2$

Concept: Values of Trigonometric Functions at Multiples and Submultiples of an Angle
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#### APPEARS IN

RD Sharma Class 11 Mathematics Textbook
Chapter 9 Values of Trigonometric function at multiples and submultiples of an angle
Q 7 | Page 42