Maharashtra State BoardSSC (English Medium) 9th Standard
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In Right Angled δ Lmn, ∠ Lmn = 90° ∠ L = 50° and ∠ N = 40°, Write the Following Ratios. (I) Sin 50° (Ii) Cos 50° (Iii) Tan 40° (Iv) Cos 40° - Geometry

Sum
In right angled `triangle` LMN, `angle` LMN = 90°, `angle` L = 50° and ∠ N = 40°, write the following ratios.

(i) sin 50° (ii) cos 50° (iii) tan 40° (iv) cos 40°
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Solution


(i) Sin 50° = `"Opposite side of ∠L"/"Hypotenuse"` = `["MN"]/["LN"]`

(ii) Cos 50° = `"Adjacent Side Of ∠L"/"Hypotenuse"` = `["LM"]/"LN"`

(iii) tan 40° = `"Opposite side of ∠N"/"Adjacent Side Of ∠N"` = `["LM"]/["MN"]`

(iv) Cos 40° = `"Adjacent Side of ∠ N"/"Hypotenuse"` = `"LM"/"LN"`

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APPEARS IN

Balbharati Mathematics 2 Geometry 9th Standard Maharashtra State Board
Chapter 8 Trigonometry
Practice Set 8.1 | Q 3 | Page 104
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