Sum
In an R-L-C parallel circuit the current through the resistor, inductor(pure), and capacitor (pure) are 20A, 15A and 40A respectively. What is the current from the supply ?draw the phasor diagram.
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Solution
`"I"_"R"=20"A"` `"I"_"L"=15"A"` `"I"_"C"=40"A"`
IS be the source current.
`"I"_"S"^2="I"_"R"^2+("I"_"L"-"I"_"C")^2`
`"I"_"S"=sqrt("I"_"R"^2+("I"_"L"-"I"_"C")^2)`
`"I"_"S"=sqrt(20^2+(15-40)^2)=sqrt(20^2+(-25)^2`
IS= 𝟑𝟐. 𝟎𝟏𝟓 A
Concept: R-L, R-C and R-LC parallel circuits
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