Sum
In an R-L-C parallel circuit the current through the resistor, inductor(pure), and capacitor (pure) are 20A, 15A and 40A respectively. What is the current from the supply ?draw the phasor diagram.
Advertisement Remove all ads
Solution
`"I"_"R"=20"A"` `"I"_"L"=15"A"` `"I"_"C"=40"A"`
IS be the source current.
`"I"_"S"^2="I"_"R"^2+("I"_"L"-"I"_"C")^2`
`"I"_"S"=sqrt("I"_"R"^2+("I"_"L"-"I"_"C")^2)`
`"I"_"S"=sqrt(20^2+(15-40)^2)=sqrt(20^2+(-25)^2`
IS= 𝟑𝟐. 𝟎𝟏𝟓 A
Concept: R-L, R-C and R-LC parallel circuits
Is there an error in this question or solution?
Advertisement Remove all ads
APPEARS IN
Advertisement Remove all ads
Advertisement Remove all ads
