MCQ

In Q. No. 1, The probability that the digit is even is

#### Options

\[\frac{4}{9}\]

\[\frac{5}{9}\]

\[\frac{1}{9}\]

\[\frac{2}{3}\]

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#### Solution

digits are chosen from 1, 2, 3, 4, 5, 6, 7, 8, 9 are placed in a box and mixed thoroughly. One digit is picked at random.

TO FIND: Probability of getting an even digit

Total number of digits is 9

Digits that are even number are 2, 4, 6, and 8

Total number of even digits is 4.

`"We know that PROBABILITY "= "Number of favourable event" /"Total number of event"`

Hence probability of getting an even digit is `4/9`

Concept: Basic Ideas of Probability

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