In a process, 701 J of heat is absorbed by a system and 394 J of work is done by the system. What is the change in internal energy for the process?

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#### Solution 1

According to the first law of thermodynamics,

Δ*U* = *q* + *W* (i)

Where,

Δ*U* = change in internal energy for a process

*q* = heat

*W* = work

Given,

*q* = + 701 J (Since heat is absorbed)

*W* = –394 J (Since work is done by the system)

Substituting the values in expression (i), we get

Δ*U* = 701 J + (–394 J)

Δ*U* = 307 J

Hence, the change in internal energy for the given process is 307 J.

#### Solution 2

Heat absorbed by the system, q = 701 J Work done by the system = – 394 J Change in internal energy (∆U) = q + w = 701 – 394 = 307 J.

Concept: The Internal Energy as a State Function - Work

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