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# In a Parallel Plate Capacitor with Air Between the Plates, Each Plate Has an Area of 6 × 10−3 M2 And the Separation Between the Plates is 3 Mm. - Physics

ConceptThe Parallel Plate Capacitor

#### Question

In a parallel plate capacitor with air between the plates, each plate has an area of 6 × 10−3 m2 and the separation between the plates is 3 mm.
(i) Calculate the capacitance of the capacitor.
(ii) If this capacitor is connected to 100 V supply, what would be the charge on each plate?
(iii) How would charge on the plates be affected, if a 3 mm thick mica sheet of K = 6 is inserted between the plates while the voltage supply remains connected?

#### Solution

(i) Capacitance,

$C = \frac{\epsilon_0 A}{d} = \frac{8 . 85 \times {10}^{- 12} \times {6 \times 10}^\min us3}{3 \times 10^\min us 4} = 17 . 7 \times 10^\min us 11 F$
(ii) Charge,
$Q = CV = 17 . 7 \times {10}^{- 11} \times 100 = 17 . 7 \times {10}^{- 9} C$
(iii) Now, C' = KC
∴ Q' = KQ = 10.62 × 10−8 C
Is there an error in this question or solution?

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Solution In a Parallel Plate Capacitor with Air Between the Plates, Each Plate Has an Area of 6 × 10−3 M2 And the Separation Between the Plates is 3 Mm. Concept: The Parallel Plate Capacitor.
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