Advertisement Remove all ads

# In Newtons’s ring experiment,what will be the order of dark ring which will have double the diameter of 40th dark ring? - Applied Physics 2

Numerical

In Newtons’s ring experiment,what will be the order of dark ring which will have double the diameter of 40th dark ring?

Advertisement Remove all ads

#### Solution

For dark ring

D_n^2 = 4  n  λ  R

D_40^2 = 4 × 40 × λ × R …………(1)

Let nth be the order of ring whose diameter is double the diameter of 40th dark ring .

(2D_40)^2 = 4 × n × λ × R…………….(2)

From equation 1 and 2

(D_40^2)/(4D_40^2) = 40/ n

n= 160

Value of n = 160

Concept: Newton’S Rings
Is there an error in this question or solution?
Advertisement Remove all ads

#### APPEARS IN

Advertisement Remove all ads
Advertisement Remove all ads
Share
Notifications

View all notifications

Forgot password?