In ∆LMN, l = 5, m = 13, n = 12 then complete the activity to show that whether the given triangle is right angled triangle or not.*(l, m, n are opposite sides of &ang;L, &ang;M, &ang;N respectively) Activity: In ∆LMN, l = 5, m = 13, n = `square` &there4; l2 = `square`, m2 = 169, n2 = 144. &there4; l2 + n2 = 25 + 144 = `square` &there4; `square` + l2 = m2 &there4;By Converse of Pythagoras theorem, ∆LMN is right angled triangle.

In ∆LMN, l = 5, m = 13, n = 12 &there4; l2 = 25, m2 = 169, n2 = 144. &there4; l2 + n2 = 25 + 144 = 169 &there4; n2 + l2 = m2 &there4;By Converse of Pythagoras theorem, ∆LMN is right angled triangle.

In ∆LMN, l = 5, m = 13, n = 12 then complete the activity to show that whether the given triangle is right angled triangle or not.*(l, m, n are opposite sides of ∠L, ∠M, ∠N respectively) Activity: In - Geometry

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Sum

In ∆LMN, l = 5, m = 13, n = 12 then complete the activity to show that whether the given triangle is right angled triangle or not.
*(l, m, n are opposite sides of ∠L, ∠M, ∠N respectively)

Activity: In ∆LMN, l = 5, m = 13, n = `square`

∴ l² = `square`, m² = 169, n² = 144.

∴ l² + n² = 25 + 144 = `square`

∴ `square` + l² = m²

∴By Converse of Pythagoras theorem, ∆LMN is right angled triangle.

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