Advertisement Remove all ads

In How Many Ways Can a Student Choose 5 Courses Out of 9 Courses If 2 Courses Are Compulsory for Every Student? - Mathematics

In how many ways can a student choose 5 courses out of 9 courses if 2 courses are compulsory for every student?

Advertisement Remove all ads

Solution

We are given that 2 courses are compulsory out of the 9 available courses,
Thus, a student can choose 3 courses out of the remaining 7 courses.
Number of ways =\[{}^7 C_3 = \frac{7!}{3! 4!} = \frac{7 \times 6 \times 5 \times 4!}{3 \times 2 \times 1 \times 4!} = 35\]

  Is there an error in this question or solution?
Advertisement Remove all ads

APPEARS IN

RD Sharma Class 11 Mathematics Textbook
Chapter 17 Combinations
Exercise 17.2 | Q 3 | Page 15
Advertisement Remove all ads

Video TutorialsVIEW ALL [1]

Advertisement Remove all ads
Share
Notifications

View all notifications


      Forgot password?
View in app×