In a Hot Water Heating System, There is a Cylindrical Pipe of Length 28 M and Diameter 5 Cm. Find the Total Radiating Surface in the System. - Mathematics

In a hot water heating system, there is a cylindrical pipe of length 28 m and diameter 5 cm. Find the total radiating surface in the system.

Solution

Given that
Height of cylinder = length of cylindrical pipe  = 28m.
Radius (r) of circular end of pipe = 5/2cm = 2.5 cm
=0.025m.
Curved surface area of cylindrical pipe =2πrh

= 2×3.14×0.025×28=4.4cm
∴ The area of radiation surface of the system is 4.4m^2  or 44000cm^2

Concept: Surface Area of Cylinder
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APPEARS IN

RD Sharma Mathematics for Class 9
Chapter 19 Surface Areas and Volume of a Circular Cylinder
Exercise 19.1 | Q 2 | Page 8

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