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In the given figure, the side QR of ΔPQR is produced to a point S. If the bisectors of ∠PQR and ∠PRS meet at point T, then prove that ∠QTR = 1/2∠QPR. - Mathematics

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In the given figure, the side QR of ΔPQR is produced to a point S. If the bisectors of ∠PQR and ∠PRS meet at point T, then prove that ∠QTR = 1/2∠QPR.

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Solution

In ΔQTR, ∠TRS is an exterior angle.

∴ ∠QTR + ∠TQR = ∠TRS

∠QTR = ∠TRS − ∠TQR ...........(1)

For ΔPQR, ∠PRS is an external angle.

∴ ∠QPR + ∠PQR = ∠PRS

∠QPR + 2∠TQR = 2∠TRS (As QT and RT are angle bisectors)

∠QPR = 2(∠TRS − ∠TQR)

∠QPR = 2∠QTR [By using equation (1)]

∠QTR = 1/2∠QPR

Concept: Angle Sum Property of a Triangle
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APPEARS IN

NCERT Class 9 Maths
Chapter 6 Lines and Angles
Exercise 6.3 | Q 6 | Page 108
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