Answer in Brief
In the given figure, prove that:
CD + DA + AB > BC
We have to prove that CD + DA + AB > BC
In ΔACD we have
CD + DA > CA (As sum of two sides of triangle is greater than third one)
⇒ CD + DA + AB > CA + AB (Adding AB both sides)
CD + DA + AB > BC Proved.
Concept: Criteria for Congruence of Triangles
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