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In the Given Figure, Prove That: Cd + Da + Ab + Bc > 2ac - Mathematics

Answer in Brief

In the given figure, prove that:

CD + DA + AB + BC > 2AC

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Solution

We have to prove that  CD + DA + AB + BC > 2AC

In  ΔABC we have

AB + BC > AC (As sum of two sides of triangle is greater than third one)   ........(1)

In  ΔACDwe have

AD + CD > AC (As sum of two sides of triangle is greater than third one)   .........(2)

Hence 

Adding (1) & (2) we get AB + BC + AC + CD > 2AC Proved.

Concept: Criteria for Congruence of Triangles
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APPEARS IN

RD Sharma Mathematics for Class 9
Chapter 12 Congruent Triangles
Exercise 12.6 | Q 7.1 | Page 81
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