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In the given figure, ∠PQR = ∠PRQ, then prove that ∠PQS = ∠PRT.
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Solution
In the given figure, ST is a straight line and ray QP stands on it.
∴ ∠PQS + ∠PQR = 180º (Linear Pair)
∠PQR = 180º − ∠PQS .........(1)
∠PRT + ∠PRQ = 180º (Linear Pair)
∠PRQ = 180º − ∠PRT ...........(2)
It is given that ∠PQR = ∠PRQ.
Equating equations (1) and (2), we obtain
180º − ∠PQS = 180° − ∠PRT
∠PQS = ∠PRT
Concept: Pairs of Angles
Is there an error in this question or solution?