Advertisement Remove all ads

In the given figure, O is the centre of the circle and ∠BDC = 42°. The measure of ∠ACB is - Mathematics

MCQ

In the given figure, O is the centre of the circle and ∠BDC = 42°. The measure of ∠ACB is

 

Options

  •  42°

  • 48°

  •  58°

  •  52°

Advertisement Remove all ads

Solution

48°

Construction: Join A and D.

Since AC is the diameter. So ADC will be 90°.

Therefore,

      `angleADB = 90 - angleBDC`

                    = 90 - 42

       `angle ADB = 48°`

 ACB = ADB = 48°      (Angle in the same segment are equal.)

  Is there an error in this question or solution?
Advertisement Remove all ads

APPEARS IN

RD Sharma Mathematics for Class 9
Chapter 15 Circles
Q 24 | Page 111
Advertisement Remove all ads
Advertisement Remove all ads
Share
Notifications

View all notifications


      Forgot password?
View in app×