Sum
In the given figure, if seg PR ≅ seg PQ, show that seg PS > seg PQ.
Advertisement Remove all ads
Solution
In △PRS, ∠PRS is an obtuse angle.
Since, a traingle can have maximum one obtuse angle.
Hence, ∠PRS is the greatest angle.
Therefore, the side opposite to ∠PRS i.e., PS is the longest side.
Now, seg PS > seg PR > seg RS
∴ seg PS > seg PQ [∵seg PR ≅ seg PQ]
Concept: Median of a Triangle
Is there an error in this question or solution?
Advertisement Remove all ads
APPEARS IN
Advertisement Remove all ads
Advertisement Remove all ads
