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MCQ
In the given figure, if AB || CD, then x =
Options
100°
105°
110°
115°
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Solution
The given figure is as follows:
It is given that AB || CD.
Let us draw a line PQ parallel to AB and CD.
It is given that,
∠1 +∠2 = 148° (i)
Since, AB || PQ Thus,∠APQangle and ∠1 are consecutive interior angles.
Therefore,
∠1 + 132° = 180°
∠1 = 180° - 132°
∠1 = 48° .. (ii)
Similarly, CD || PQ. Thus, x angle and ∠2 are corresponding angles.
Therefore,
∠2 = x (iii)
On substituting (ii) and (iii) in (i):
48° + x = 148°
x = 148° - 48°
x = 100°
Concept: Parallel Lines and a Transversal
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