Question

 In Given Figure, find tan P – cot R.

 

Answer 1

Applying Pythagoras theorem for ΔPQR, we obtain

PR² = PQ² + QR²

(13 cm)² = (12 cm)² + QR²

169 cm² = 144 cm² + QR²

25 cm² = QR²

QR = 5 cm

`tan P = ("Side opposite to"angle P)/("Side adjacent to"angleP) = (QR)/(PQ)`

= 5/12

`cot R = ("Side opposite to"angle R)/("Side adjacent to"angleR) = (QR)/(PQ)`

= 5/12

tan P - cot R = ` 5/12 - 5/12 = 0`