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In the Given Figure, Bc ⊥ Ab, Ad ⊥ Ab, Bc = 4, Ad = 8, Then Find a ( δ a B C ) a ( δ a D B ) . - Geometry

In the given figure, BC ⊥ AB, AD ⊥ AB, BC = 4, AD = 8, then find \[\frac{A\left( ∆ ABC \right)}{A\left( ∆ ADB \right)} .\] 

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Solution

Given:
BC = 4
AD = 8 

\[\therefore \frac{A\left( \bigtriangleup ABC \right)}{A\left( \bigtriangleup ADB \right)} = \frac{AB \times BC}{AB \times AD}\]
\[ = \frac{BC}{AD} \left[ \because BC = 4 \text{ and } AD = 8 \right]\]
\[ = \frac{4}{8}\] 

\[= \frac{1}{2}\]

 

Concept: Similar Triangles
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APPEARS IN

Balbharati Mathematics 2 Geometry 10th Standard SSC Maharashtra State Board
Chapter 1 Similarity
Practice Set 1.1 | Q 2 | Page 6
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