Advertisement Remove all ads
Advertisement Remove all ads
Advertisement Remove all ads
In the given figure, AP || BQ || CR. Prove that ar (AQC) = ar (PBR).
Advertisement Remove all ads
Solution
Since ΔABQ and ΔPBQ lie on the same base BQ and are between the same parallels AP and BQ,
∴ Area (ΔABQ) = Area (ΔPBQ) ... (1)
Again, ΔBCQ and ΔBRQ lie on the same base BQ and are between the same parallels BQ and CR.
∴ Area (ΔBCQ) = Area (ΔBRQ) ... (2)
On adding equations (1) and (2), we obtain
Area (ΔABQ) + Area (ΔBCQ) = Area (ΔPBQ) + Area (ΔBRQ)
⇒ Area (ΔAQC) = Area (ΔPBR)
Concept: Corollary: Triangles on the same base and between the same parallels are equal in area.
Is there an error in this question or solution?