In the given figure, AC is a diameter of a circle, whose centre is O. A circle is described on AO
as diameter. AE, a chord of the larger circle, intersects the smaller circle at B. prove that AB =
Then ∠OBA = 90°
(Angle in a semicircle is a right angle)
We know the perpendicular drawn from the centre to a chord bisects the chord.
∴ AB = BE
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- Chord Properties - the Perpendicular to a Chord from the Center Bisects the Chord (Without Proof)