In the given figure ABCD is quadrilateral in which diagonal BD = 24 cm, AL ⊥ BD and CM ⊥ BD such that AL = 9cm and CM = 12 cm. Calculate the area of the quadrilateral.

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#### Solution

We have,

BD=24 cm AL=9 cm CM=12 cm AL⊥ BD and CM ⊥BD

Area of the quadrilateral = ar (Δ ABD)+ar (Δ BCD)

= `1/2xx BDxxAL+1/2 xxBDxxCM`

=`1/2xx24xx9+1/2xx24xx12`

=`108+144`

=`252 cm^2`

So, the area of the quadrilateral ABCD is 252`cm^2`

Concept: Area of Circle

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