Question

In the given figure, ABC is an isosceles triangle whose side AC is produced to E. Through C, CD is drawn parallel to BA. The value of x is

Options

• 52°

• 76°

• 156°

• 104°

Answer 1

We are given that;

ΔABC , is isosceles 

AB = AC

∠B = ∠C

∠C = 52

And  AB || CD

We are asked to find angle x

From the figure we have

∠ACB = 52°

Therefore,

∠A = `180° - 2 xx 52° `

      = 76°

Since AB || DC , so

∠ACD = ∠BAC

           = 76°

Now 

x + 76 = 180

           = 180 - 76

            = 104