In the given figure, ABC and ABD are two triangles on the same base AB. If line-segment CD is bisected by AB at O, show that ar (ABC) = ar (ABD).
Line-segment CD is bisected by AB at O. Therefore, AO is the median of
∴ Area (ΔACO) = Area (ΔADO) ... (1)
Considering ΔBCD, BO is the median.
∴ Area (ΔBCO) = Area (ΔBDO) ... (2)
Adding equations (1) and (2), we obtain
Area (ΔACO) + Area (ΔBCO) = Area (ΔADO) + Area (ΔBDO)
⇒ Area (ΔABC) = Area (ΔABD)
Concept: Corollary: Triangles on the same base and between the same parallels are equal in area.
Is there an error in this question or solution?
Video TutorialsVIEW ALL 
Video Tutorials For All Subjects
- Corollary: Triangles on the same base and between the same parallels are equal in area.