#### Question

In the given diagram, chord AB = chord BC.

(i) what is the relation between arcs AB and BC?

(ii) what is the relation between ∠AOB and ∠BOC?

(iii) If arc AD is greater than arc ABC, then what is the relation between chords AD and AC?

(iv) If ∠AOB = 50°, find the measure of angle BAC.

#### Solution

Join OA, OB, OC and OD.

(i) Arc AB = Arc BC [ ∵ Equal chords subtends equal arcs]

(ii) ∠AOB = ∠BOC [ ∵ Equal chords subtends equal arcs]

(iii) If arc AD > arc ABC, then chord AD > AC

(iv) ∠AOB = 50°

But ∠AOB = ∠BOC [from (ii) above]

∴ ∠BOC = 50°

Now arc BC subtends ∠BOC at the center and ∠BAC at The remaining part of the circle.

∴ `∠BAC = 1/2 ∠BOC = 1/2xx 50° = 25°`

Is there an error in this question or solution?

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In the Given Diagram, Chord Ab = Chord Bc.I) What is the Relation Between Arcs Ab and Bc? (Ii) What is the Relation Between ∠Aob and ∠Boc?If Arc Ad is Greater than Arc Abc, Then What is the Relation Concept: Arc and Chord Properties - the Angle that an Arc of a Circle Subtends at the Center is Double that Which It Subtends at Any Point on the Remaining Part of the Circle.

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