#### Question

In a given coil of self-inductance of 5 mH, current changes from 4 A to 1 A in 30 ms. Calculate the emf induced in the coil.

#### Solution

Self inductance, L=5 mH=5×10^{−3} HChange in current,

dI=(1−4)=−3 A

Change in time, `dt=30 ms=30×10−3 s`

The emf induced in the coil is given by ` e=−L(dI)/(dt)`

`⇒e=((−5xx10^(−3) )xx(−3))/(30×10^(−3))`

`⇒e=0.5 V`

Is there an error in this question or solution?

Solution In a Given Coil of Self-inductance of 5 Mh, Current Changes from 4 a to 1 a in 30 ms. Calculate the Emf Induced in the Coil. Concept: Inductance - Self-Inductance.