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In the Following Systems of Equations Determine Whether the System Has a Unique Solution, No Solution Or Infinitely Many Solutions. in Case There is a Unique Solution, Find It: 3x - 5y = 20 6x - 10y = 40 - Mathematics

In the following systems of equations determine whether the system has a unique solution, no solution or infinitely many solutions. In case there is a unique solution, find it:

3x - 5y = 20

6x - 10y = 40

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Solution

3x - 5y = 20

6x - 10y = 40

Compare it with

`a_1x + by_1 + c_1 = 0`

`a_1x + by_2 + c_2 = 0`

We get

`a_1 = 3, b_1 = -5, c_1 = -20`

`a_2 = 6, b_2 = -10, c_2 = -40`

`a_1/a_2 = 3/6, b_1/b_2 = (-5)/(-10) , c_1/c_2 = (-20)/(-40)`

Simplifying it we get

`a_1/a_2 = 1/2, b_1/b_2 = 1/2 , c_1/c_2 = 1/2`

Hence

`a_1/a_2 = b_1/b_2 = c_1/c_2`

So both lines are coincident and overlap with each other
So, it will have infinite or many solutions

  Is there an error in this question or solution?
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APPEARS IN

RD Sharma Class 10 Maths
Chapter 3 Pair of Linear Equations in Two Variables
Exercise 3.5 | Q 3 | Page 73
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