Advertisement Remove all ads

In the following figure, a tangent segment PA touching a circle in A and a secant PBC is shown. If AP = 15, BP = 10, find BC - Geometry

Advertisement Remove all ads
Advertisement Remove all ads
Advertisement Remove all ads

In the following figure, a tangent segment PA touching a circle in A and a secant PBC is shown. If AP = 15, BP = 10, find BC.

Advertisement Remove all ads

Solution

PA is a tangent segment and PBC is the secant.

`therefore PB xx PC=PA^2` ........(Relationship to Tangent-Secant Theorem)

`therefore 10xxPC=15^2`

`PC=225/10=22.5`

`Now , PB+BC=PC`

`therefore 10+BC=22.5`

`therefore BC=22.5-10= 12.5`

Concept: Tangent - Secant Theorem
  Is there an error in this question or solution?

Video TutorialsVIEW ALL [2]

Advertisement Remove all ads
Share
Notifications

View all notifications


      Forgot password?
View in app×