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In the following figure seg AB ⊥ seg BC, seg DC ⊥ seg BC. If AB = 2 and DC = 3, find `(A(triangleABC))/(A(triangleDCB))`

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#### Solution

In the following figure ΔABC and ΔDCB have a comman base BC.

`therefore(A(triangleABC))/(A(triangleDCB))=(AB)/(DC)`

(∵The ratio of areas of two triangles with the same base is equal to the ratio of their corresponding heights.)

`therefore(A(triangleABC))/(A(triangleDCB))=2/3`

Concept: Properties of Ratios of Areas of Two Triangles

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