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In the following figure RP: PK= 3:2, then find the value of A(ΔTRP):A(ΔTPK). - Geometry

Sum

In the following figure RP: PK= 3:2, then find the value of A(ΔTRP):A(ΔTPK).

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Solution

Ratio of the areas of two triangles with common or equal heights is equal to the ratio of their corresponding bases.

`(A(triangleTRP))/(A(triangleTPK))="RP"/"PK"=3/2`

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