# In the following figure RP: PK= 3:2, then find the value of A(ΔTRP):A(ΔTPK). - Geometry

Sum

In the following figure RP: PK= 3:2, then find the value of A(ΔTRP):A(ΔTPK).

#### Solution

Ratio of the areas of two triangles with common or equal heights is equal to the ratio of their corresponding bases.

(A(triangleTRP))/(A(triangleTPK))="RP"/"PK"=3/2

Concept: Properties of Ratios of Areas of Two Triangles
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