In the Following Figure, Ray Pa is a Tangent to the Circle at a and Pbc is a Secant. If Ap = 15, Bp = 10, Then Find Bc. - SSC (English Medium) Class 10th Board Exam - Geometry
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In the following figure, ray PA is a tangent to the circle at A and PBC is a secant. If AP = 15, BP = 10, then find BC.
In the given figure, PA is a tangent segment and PBC is the secant
∴ PB x PC = PA2
`:. 10 xx PC = 15^2`
`:. PC = 225/10 = 22.5`
NOw PB + BC = PC .............(P - B - C)
∴ 10 + BC = 22.5
∴ BC = 22.5 - 10 = 12.5
Therefore BC = 12.5
Is there an error in this question or solution?
Solution In the Following Figure, Ray Pa is a Tangent to the Circle at a and Pbc is a Secant. If Ap = 15, Bp = 10, Then Find Bc. Concept: Tangent - Secant Theorem.