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In the following figure, if m(are DXE) = 90° and m(are AYC) = 30°. Find ∠DBE.
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Solution
By inscribed angle theorem,
m∠AEB=(1/2) × m∠AYC=(1/2) × 30o = 15o ...(1)
m∠EAD=(1/2) × m∠DXE=(1/2) × 90o = 45o ...(2)
∠DBE + ∠AEB = ∠EAD
⇒ m∠DBE + 15o = 45o
⇒ m∠DBE = 45o - 15o = 30o
Concept: Areas of Sector and Segment of a Circle
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