Share
Notifications

View all notifications
Advertisement

In the following figure, if ΔABE ≅ ΔACD, show that ΔADE ∼ ΔABC. - Mathematics

Login
Create free account


      Forgot password?

Question

In the following figure, if ΔABE ≅ ΔACD, show that ΔADE ∼ ΔABC.

Solution

It is given that ΔABE ≅ ΔACD.

∴ AB = AC [By CPCT] (1)

And, AD = AE [By CPCT] (2)

In ΔADE and ΔABC,

`(AD)/(AB) = (AE)/(AC) `  [Dividing equation 2 by 1]

A = ∠A [Common angle]

∴ ΔADE ∼ ΔABC [By SAS similarity criterion]

  Is there an error in this question or solution?
Advertisement

APPEARS IN

 NCERT Solution for Mathematics Textbook for Class 10 (2019 (Latest))
Chapter 6: Triangles
Ex. 6.3 | Q: 6 | Page no. 140
Advertisement
In the following figure, if ΔABE ≅ ΔACD, show that ΔADE ∼ ΔABC. Concept: Criteria for Similarity of Triangles.
Advertisement
View in app×