In the following figure, if ΔABE ≅ ΔACD, show that ΔADE ∼ ΔABC.
It is given that ΔABE ≅ ΔACD.
∴ AB = AC [By CPCT] (1)
And, AD = AE [By CPCT] (2)
In ΔADE and ΔABC,
`(AD)/(AB) = (AE)/(AC) ` [Dividing equation 2 by 1]
A = ∠A [Common angle]
∴ ΔADE ∼ ΔABC [By SAS similarity criterion]