Advertisement Remove all ads

In the following figure, DE || OQ and DF || OR, show that EF || QR - Mathematics

Advertisement Remove all ads
Advertisement Remove all ads
Advertisement Remove all ads

In the following figure, DE || OQ and DF || OR, show that EF || QR

Advertisement Remove all ads

Solution

In Δ POQ, DE || OQ

`:. (PE)/(EQ) = (PD)/(DO)` .... (Basic Proportionality theorem)  (i)

In ΔPOR, DF || OR

`:. (PF)/(FR) = (PD)/(DO)` (Basic Proportionality theorem)  (ii)

From i and ii we obtain

`(PE)/(EQ) = (PF)/(FR)`

:. EF || QR (Converse of basic proportionally theorem)

Concept: Similarity of Triangles
  Is there an error in this question or solution?

APPEARS IN

NCERT Class 10 Maths
Chapter 6 Triangles
Exercise 6.2 | Q 5 | Page 129
Advertisement Remove all ads
Share
Notifications

View all notifications


      Forgot password?
View in app×