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In the following figure, DE || AC and DF || AE. Prove that (BF)/(FE)=(BE)/(EC) - Mathematics

In the following figure, DE || AC and DF || AE. Prove that `(BF)/(FE)=(BE)/(EC)`

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Solution

In ΔABC, DE || AC

`:.(BD)/(DA)=(BE)/(EC)`   (Basic Proportionality Theorem)...(i)

In ΔBAE,DF || AE

:. `(BD)/(DA) = (BF)/(FE)`  (Basic Proportionality Theorem)  ... (ii)

∴ From i and ii we obtain

`(BE)/(EC)=(BF)/(FE)`

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APPEARS IN

NCERT Class 10 Maths
Chapter 6 Triangles
Exercise 6.2 | Q 4 | Page 128
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