Answer 1

We have been given that,

x² + x + 1 = 0, x = 0, x = 1

Now if x = 0 is a solution of the equation then it should satisfy the equation.

So, substituting x = 0 in the equation, we get

x² + x + 1

= (0)² + 0 + 1

= 1

Hence x = 0is not a solution of the given quadratic equation.

Also, if x = 1is a solution of the equation then it should satisfy the equation.

So, substituting x = 1 in the equation, we get

x² + x + 1

= (1)² + 1 + 1

= 3

Hence x = 1 is not a solution of the quadratic equation.

Therefore, from the above results we find out that both x = 0 and x = 1are not a solution of the given quadratic equation.