In the following, determine whether the given values are solutions of the given equation or not:

x^{2} + x + 1 = 0, x = 0, x = 1

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#### Solution

We have been given that,

x^{2} + x + 1 = 0, x = 0, x = 1

Now if x = 0 is a solution of the equation then it should satisfy the equation.

So, substituting x = 0 in the equation, we get

x^{2} + x + 1

= (0)^{2} + 0 + 1

= 1

Hence x = 0is not a solution of the given quadratic equation.

Also, if x = 1is a solution of the equation then it should satisfy the equation.

So, substituting x = 1 in the equation, we get

x^{2} + x + 1

= (1)^{2} + 1 + 1

= 3

Hence x = 1 is not a solution of the quadratic equation.

Therefore, from the above results we find out that both x = 0 and x = 1are not a solution of the given quadratic equation.

Concept: Quadratic Equations

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