Question
In the following, determine whether the given values are solutions of the given equation or not:
x2 - 3x + 2 = 0, x = 2, x = -1
Solution
We have been given that,
x2 - 3x + 2 = 0, x = 2, x = -1
Now if x = 2 is a solution of the equation then it should satisfy the equation
So, substituting x = 2 in the equation we get
x2 - 3x + 2
= (2)2 - 3(2) + 2
= 4 - 6 + 2
= 0
Hence, x = 2 is a solution of the given quadratic equation.
Also, if x = -1 is a solution of the equation then it should satisfy the equation
So, substituting x = -1 in the equation, we get
x2 - 3x + 2
= (-1)2 - 3(-1) + 2
= 1 + 3 + 2
= 6
Hence x = -1 is not a solution of the quadratic equation
Therefore, from the above results we find out that x = 2 is a solution and x = -1 is not a solution of the given quadratic equation.
